A particle is projected from ground at an angle 60 with horizontal with a speed of 10 root 3. .
- A particle is projected from ground at an angle 60 with horizontal with a speed of 10 root 3. Solution: Initial velocity, vi = 2cosθi^+4sinθj ^= 5 3i^+ 15j ^ Final velocity vector (after 2s), vf = ucosθi^+ (usinθ − gt)j ^ = 5 3i^−5j ^ Now, vi ⋅ vf = 25 ×3−15 ×5 = 0 ∴ vi ⊥ vf Where T is the time, u is the initial velocity, α, β are the angles and g is the acceleration due to gravity. 8 m C. Jul 8, 2019 · A particle is projected at angle 60º with speed 10√3 , from the point ' A ' as shown in the fig. A particle is projected at an angle 60∘ with speed 10(√3)m/s, from the point A, as shown in the figure. 24. ` The radius of curvature of the path of the particle, when its velocity. T = 2 × 10 3 × sin (60 ∘ 30 ∘) 10 × cos 30 ∘ A. 2 m` A particle is projected at an angle of 60∘ above the horizontal with a speed of 10m/s. The diagram representing the parameters: Substitute the values of the acceleration due to gravity, the initial velocity and the angle values in the above equation. 10. 4 m` D. `15. Aug 6, 2019 · A particle A is projected from the ground with an initial velocity of 10m/s at an angle at 60° with horizontal. Particle is projected from ground at an angle 60°with horizontal with a speed of 10√3 m/s from point A. A particle is projected at an angle of 60∘ above the horizontal with a speed of 10m/s. 4 m D. At the same time the wedge is made to move with speed 10√3 towards right as shown in the figure. 6 m B. The time in second after which particle will hit the wedge will be Aniket kumar , 7 Years ago Grade 11 1 Answers To solve the problem step by step, we will follow the trajectory of the projectile and determine the radius of curvature when the velocity makes an angle of 30∘ with the horizontal. `10. At the same time the wedge is made to move with speed 10(√3)m/s towards right as shown in the figure. `24. makes an angle of `30^ (@)` with horizontal is : ` (g=10 m//s^ (2)` A. Dec 8, 2024 · To find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with the horizontal, we can use the formula for the radius of curvature in projectile motion. The speed of the particle at this instant is A particle is projected from ground at an angle 60 ∘ with horizontal with a speed of 10 3 m / s from point A as shown. After some time the direction of its velocity makes an angle of 30∘ above the horizontal. At the same time the sufficient long wedge is made to move with constant velocity of 10 3 towards right as shown in figure. Jul 6, 2019 · A particle is projected from the ground at an angle of `60^ (@)` with horizontal at speed `u = 20 m//s. At the same time the sufficient long wedge is made to move with constant velocity of 10√3m/s towards right. 2 m A particle is projected at an angle of 60∘ above the horizontal with a speed of 10m/s. 8 m` C. 6 m` B. From what height h should another particle B be projected horizontally with velocity 5 m/s so that both the particles collide on ground at point C if both are projected simultaneously (g = 10m/s2). `12. 15. Dec 22, 2021 · A particle is projected from the ground at an angle of `60^ (@)` with horizontal at speed `u = 20 m//s. 12. rcbked owz vdrr nvvrdgf cof xog mnsgh layql rqc vgrhy